Calculate all the angles of a quadrilateral if they are in the ratio 2:5:4:1?
As the angles are in the ratio 2:5:4:1, they can be written as-
2x, 5x, 4x, and x
Now, as the sum of the angles of a quadrilateral is 360°,
2x + 5x + 4x + x = 360°
Or, x = 30°
Now, all the angles will be,
2x =2 × 30° = 60°
5x = 5 × 30° = 150°
4x = 4 × 30° = 120°, and
x = 30
Calculate all the angles of a parallelogram if one of its angles is twice its adjacent angle?
Let the angle of the parallelogram given in the question statement be “x”.
Now, its adjacent angle will be 2x.
It is known that the opposite angles of a parallelogram are equal.
So, all the angles of a parallelogram will be x, 2x, x, and 2x
As the sum of interior angles of a parallelogram = 360°,
x + 2x + x + 2x = 360°
Or, x = 60°
Thus, all the angles will be 60°, 120°, 60°, and 120°.
In a trapezium ABCD, AB∥CD. Calculate ∠C and ∠D if ∠A = 55° and ∠B = 70°?
In a trapezium ABCD, A + D = 180° and B + C = 180°
So, 55° + D = 180°
Or, D = 125°
Similarly,
70° + C = 180°
Or, C = 110°
Is it possible to draw a quadrilateral whose all angles are obtuse angles?
It is known that the sum of angles of a quadrilateral is always 360°. To have all angles as obtuse, the angles of the quadrilateral will be greater than 360°. So, it is not possible to draw a quadrilateral whose all angles are obtuse angles.
In a rectangle, one diagonal is inclined to one of its sides at 25°. Measure the acute angle between the two diagonals.?
Let ABCD be a rectangle where AC and BD are the two diagonals which are intersecting at point O.
Now, assume BDC = 25° (given)
Now, BDA = 90° – 25° = 65°
Also, DAC = BDA, (as diagonals of a rectangle divide the rectangle into two congruent right triangles)
So, BOA = the acute angle between the two diagonals = 180° – 65° – 65° = 50°
The paint in a certain container is sufficient to paint an area equal to 9.375 m^2 . How many bricks of dimensions 22.5 cm × 10 cm × 7.5 cm can be painted out of this container?
Surface area:
Surface area of a solid object is a measure of the total area that the surface of the object occupies and it is always measured in square unit.
Hence surface area is also known as total surface area TSA.
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Given:
Dimension of brick = l=22.5 cm, b=10 cm, c=7.5 cm
Total surface area of a container= 9.375 m²
Total surface area of a brick = 2(lb + bh + lh)
= 2(22.5×10 + 10×7.5 + 22.5×7.5)
= 2(225 + 75 + 168.75)
= 2×468.75
= 937.5 cm²
= 937.5/100×100 m²
Number of bricks that painted out of this container= total area painted by containers paint / total surface area of a brick
=9.375/ (937.5/100×100)
=( 9.375×100×100) / 937.5
= 937500/ 9375= 100
Hence,100 bricks can be painted out.
The weight (in kg) of 7 students of a class are 44, 52, 55, 60, 50, 49, 45.
Find the median weight?
Let’s arrange the data given in ascending order – 44, 45, 49, 50, 52, 55, 60.
n= 7, so it’s an odd number
Median = (n+1) / 2 observations
= (7+1)/ 2 = (8/2)th observation = 4th observation = 50 kg
The Number of books issued to 13 students in a class are:
25, 19, 24, 23, 29, 31, 19, 20, 22, 26, 17, 35, 21.
Find the median no. of books for the above data?
Let’s arrange the data given in ascending order – 17, 19, 19, 20, 21, 22, 23, 24, 25, 26, 29,31,35.
n= 13, so it’s an odd number
Median = (n+1) / 2 observations
= (13+1)/ 2 = (14/2)th observation = 7th observation = 23